Transcript
Chapter 1 Problem Solutions
111 .. (a) 25 × 10 4 Ω = 250 × 103 Ω = 250kΩ . × 10 2 Ω = 350Ω (b) 0.035 × 10 4 Ω = 35
(c) 0.00045F = 450 × 10 −6 F = 450µ F (d) 0.003 × 10 −7 F = 0.3 × 10 −9 F = 0.3nF (e) 0.005 × 10 −2 H = 50 × 10 −6 H = 50 µ H 11 . .2 5280ft 12in 2.54cm 1m 1km × × × × = 48.28km 1mile 1ft 1in 100cm 1000m 12in 1000mils (b) 1ft × × = 12,000mils 1ft 1in 1m 3ft 12in 2.54cm (c) 100yds × × × × = 9144 . m 1yd 1ft 1in 100cm 100cm 1000mils 1m 1in (d) 5mm × × × × = 196.85mils 2.54cm 1000mm 1m 1in 1m 100cm 1in 1000mils (e) 20µ m × 6 × × × = 0.7874mils 1m 2.54cm 1in 10 µ m
(a) 30miles ×
(f) 880yds ×
1m 3ft 12in 2.54cm × × × = 804.67m 1yd 1ft 1in 100cm
1.21 . (a) λ = (b) λ = (c) λ = (d) λ = (e) λ =
3 × 108 m s . km = 2,071.2 miles = 33333 90 Hz
3 × 108 m s 103 Hz
= 300 km = 186.41 miles
3 × 108 m s 350 × 103 Hz 3 × 108 m s
1.2 × 106 Hz 3 × 108 m s
35 × 106 Hz
= 85714 . m = 0.533 miles
= 250 m = 820.2 ft = 8.57 m = 28.12 ft
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(f) λ = (g) λ = (h) λ = (i) λ =
3 × 108 m s 110 × 10 6 Hz 3 × 108 m s
335 × 106 Hz 3 × 108 m s 6 × 109 Hz
3 × 108 m s 45 × 109 Hz
= 2.73 m = 8.95 ft = 89.55 cm = 2.94 ft
= 5 cm = 1.97 in = 6.67 mm = 262.5 mils
1.2.2 (a)
λ=
3 × 108 m s = 5 × 10 6 m 50 miles = 80.46 km 60 Hz
(
)
1 λ 80.46 × 103 m = ? × 5 × 10 6 m ∴ ? = 0.0161 λ = 14 4244 3 62 14243 length
λ
(b)
λ=
3 × 108 m s
= 600 m 500 feet = 152.4 m 500 × 103 Hz 152.4 m = ? × (600 m ) ∴ ? = 0.254 λ 12 4 4 3 12 4 4 3 λ
length
(c)
λ=
3 × 108 m s
= 2.73 m 4.5 feet = 1.37 m 110 × 10 6 Hz 137 . m = ? × (2.73 m ) ∴ ? = 0.5 λ 123 12 4 4 3 length
λ
(d)
λ=
15 . × 108 m s
= 7.5 cm 2 inches = 5.08 cm 2 × 109 Hz 5.08 cm = ? × (7.5 cm ) ∴ ? = 0.677 λ 123 4 12 4 4 3 length
λ
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1.2.3 (a)
β = 2.2 × 10 −2 T=
rad m v ω , f = 1 MHz, v = = 2.856 × 108 , λ = = 285.6 m, m s f β
d = 10.5 µ s, φ = β d = 66 rad = 3781.5o v
(b)
rad m v ω , f = 3 GHz, v = = 2.5 × 108 , λ = = 833 . mm, m s f β d 4 inches = 0.102 m, T = = 0.41 ns, φ = β d = 7.66 rad = 438.92 o v
β = 75.4
(c)
rad m v ω , f = 150 MHz, v = = 2.99 × 108 , λ = = 1995 . m, m s f β d 20 feet = 6.1m, T = = 20.4 ns, φ = β d = 19.2 rad = 1100.2o v
β = 315 .
(d)
rad m v ω , f = 3 kHz, v = = 15 . × 108 , λ = = 50 km, m s f β d 50 miles = 80.5 km, T = = 0.54 ms, φ = β d = 1014 . rad = 580.9o v
β = 0126 . × 10 −3
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