98. (a) From Newton’s second law, the magnitude of the maximum force on the passenger from the floor is given by
Fmax − mg = ma where a = amax = 2.0 m s 2 we obtain FN = 590 N for m = 50 kg. (b) The direction is upward. (c) Again, we use Newton’s second law, the magnitude of the minimum force on the passenger from the floor is given by
Fmin − mg = ma where a = amin = − 3.0 m s 2 . Now, we obtain FN = 340 N. (d) The direction is upward. (e) Returning to part (a), we use Newton’s third law, and conclude that the force exerted G by the passenger on the floor is | FPF | = 590 N. (f) The direction is downward.
