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Solução Do Halliday 8.ed.vol.1. Cap.5 - Ch05 - P004

A solução do Halliday da 8ª edição volume 1. do Cap.5

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    December 2018

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    ch05 Halliday

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→ ^ ^ 4. We note that m a = (–16 N) i + (12 N) j . With the other forces as specified in the problem, then Newton’s second law gives the third force as → → → → F3 = m a – F1 – F2 =(–34 N) ^i − (12 N) ^j.