Resolução - Halliday - Volume 3 - Eletricidade E Magnetismo - P23 039

Transcript

39. (a) We use ∆x = vavg t = vt/2: v= 2(2.0 × 10−2 m) 2∆x = = 2.7 × 106 m/s . t 1.5 × 10−8 s (b) We use ∆x = 12 at2 and E = F/e = ma/e: E= 2(2.0 × 10−2 m)(9.11 × 10−31 kg) 2∆xm ma = = 1.0 × 103 N/C . = e et2 (1.60 × 10−19 C)(1.5 × 10−8 s)2