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Resolução - Halliday - Volume 3 - Eletricidade E Magnetismo - P23 026

Exercícios Resolvidos.

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26. From Eq. 23-26 E = = σ 2ε0  z 1− √ 2 z + R2    2 12 cm 5.3 × 10−6 C/m    1 − = 6.3 × 103 N/C . C2 2 + (2.5 cm)2 2 8.85 × 10−12 N·m (12 cm) 2