Resolução - Halliday - Volume 3 - Eletricidade E Magnetismo - P22 034

Transcript

34. Let the two charges be q1 and q2 . Then q1 + q2 = Q = 5.0 × 10−5 C. We use Eq. 22-1: 
2 q1 q2 8.99 × 109 N·m 2 C . 1.0 N = (2.0 m)2 We substitute q2 = Q − q1 and solve for q1 using the quadratic formula. The two roots obtained are the values of q1 and q2 , since it does not matter which is which. We get 1.2 × 10−5 C and 3.8 × 10−5 C.