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Halliday-cap 22-vol.3- Rar - P22 037

Solução do exercícios 1 aqo 51 do Capítulo 22- Cargas Elétricas- 4 ed. VOL.3 A solução dos exercícios está em inglês

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37. The net charge carried by John whose mass is m is roughly q = = = mNA Ze M   (90 kg)(6.02 × 1023 molecules/mol)(18 electron proton pairs/molecule) 1.6 × 10−19 C (0.0001) 0.018 kg/mol (0.0001) 8.7 × 105 C , and the net charge carried by Mary is half of that. So the electrostatic force between them is estimated to be   2 q(q/2) (8.7 × 105 C)2 9 N·m F ≈k = 8.99 × 10 ≈ 4 × 1018 N . 2 2 d C 2(30 m)2