Halliday 2 Cap 18 - P18 060

Transcript

60. The altitude H and the horizontal distance x for the legs of a right triangle, so we have H = x tan θ = vp t tan θ = 1.25vt sin θ where v is the speed of sound, vp is the speed of the plane and
  v  v −1 θ = sin = 53.1◦ . = sin−1 vp 1.25v Thus the altitude is H = x tan θ = (1.25)(330 m/s)(60 s)(tan 53.1◦ ) = 3.30 × 104 m .