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Solução Do Halliday 8.ed.vol.1. Cap.5 - Ch05 - P020

A solução do Halliday da 8ª edição volume 1. do Cap.5

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    December 2018

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    ch05 Halliday

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G 20. We take rightwards as the +x direction. Thus, F1 = (20 N )iˆ . In each case, we use G G G Newton’s second law F1 + F2 = ma where m = 2.0 kg. G G (a) If a = (+10 m/s 2 ) ˆi , then the equation above gives F2 = 0. G G ˆ (b) If , a = (+ 20m/s 2 ) ˆi, then that equation gives F2 = (20 N)i. G G (c) If a = 0, then the equation gives F2 = (−20 N) ˆi. G G (d) If a = (−10 m/s 2 ) ˆi, the equation gives F2 = (−40 N) ˆi. G G (e) If a = (− 20 m/s 2 ) ˆi, the equation gives F2 = (−60 N) ˆi.