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Resolução - Halliday - Volume 3 - Eletricidade E Magnetismo - P23 031

Exercícios Resolvidos.

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31. We combine Eq. 23-9 and Eq. 23-28 (in absolute values).   p 2ke p F = |q|E = |q| = 3 2πε0 z z3 where we use Eq. 22-5 in the last step. Thus, we obtain     2 8.99 × 109 N·m2 /C2 1.60 × 10−19 C 3.6 × 10−29 C·m F = 3 (25 × 10−9 m) which yields a force of magnitude 6.6 × 10−15 N. If the dipole is oriented such that p is in the +z direction, then F points in the −z direction.