Resolução - Halliday - Volume 3 - Eletricidade E Magnetismo - P23 028

Transcript

28. Eq. 23-28 gives


= F = m
a = − m
a E q (−e) e using Newton’s second law. Therefore, with east being the ˆi direction,    −31 kg
9 2ˆ
= − 9.11 × 10 E i = −0.0102 N/C ˆi m/s 1.80 × 10 1.60 × 10−19 C which means the field has a magnitude of 0.0102 N/C and is directed westward.