Resolução - Halliday - Volume 3 - Eletricidade E Magnetismo - P22 021

Transcript

21. (a) The magnitude of the force between the (positive) ions is given by F = (q)(q) q2 = k 4πε0 r2 r2 where q is the charge on either of them and r is the distance between them. We solve for the charge: 
F 3.7 × 10−9 N −10 q=r m) = 3.2 × 10−19 C . = (5.0 × 10 k 8.99 × 109 N·m2 /C2 (b) Let N be the number of electrons missing from each ion. Then, N e = q, or N= 3.2 × 10−19 C q = =2. e 1.6 × 10−19 C