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Halliday-cap 22-vol.3- Rar - P22 048

Solução do exercícios 1 aqo 51 do Capítulo 22- Cargas Elétricas- 4 ed. VOL.3 A solução dos exercícios está em inglês

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48. When sphere C touches sphere A, they divide up their total charge (Q/2 plus Q) equally between them. Thus, sphere A now has charge 3Q/4, and the magnitude of the force of attraction between A and B becomes    F =k Q 4 3Q 4 d2 = 4.68 × 10−19 N .