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Halliday 2 Cap 18 - P18 098

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    December 2018
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98. (a) We observe that “third lowest ... frequency” corresponds to harmonic number n = 5 for such a system. Using Eq. 18-41, we have f= nv 4L =⇒ 750 = so that v = 360 m/s. (b) As noted, n = 5; therefore, f1 = 750/5 = 150 Hz. 5v 4(0.60)