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Halliday 2 Cap 18 - P18 084

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    December 2018
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84. Let  be the length of the rod. Then the time of travel for sound in air (speed vs ) will be ts = /vs . And the time of travel for compressional waves in the rod (speed vr ) will be tr = /vr . In these terms, the problem tells us that   1 1 − ts − tr = 0.12 s =  . vs vr Thus, with vs = 343 m/s and vr = 15vs = 5145 m/s, we find  = 44 m.