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Halliday 2 Cap 18 - P18 081

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    December 2018
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81. We find the difference in the two applications of the Doppler formula:     340 + 25 340 25 f2 − f1 = 37 = f − =f 340 − 15 340 − 15 340 − 15 which leads to f = 481 ≈ 480 Hz.