Halliday 2 Cap 18 - P18 006

Transcript

6. (a) The time it takes for sound to travel in air is ta = L/v, while it takes tm = L/V for the sound to travel in the metal. Thus L L L(V − v) t = ta − tm = − = . v V Vv (b) Using the values indicated (see Table 18-1), we obtain L= 1.00 s t = = 364 m . 1/v − 1/V 1/(343 m/s) − 1/(5941 m/s)